In this paper, we define a braid invariant, the purified determinant P(b)P(b) of a braid bb, considering the determinant of the crossing matrix of a pure braid derived from bb, and show that P(b1b2)=P(b2b1)P(b1b2)=P(b2b1) for any pair of nn-braids b1b1 and b2b2.
生成讲解博客的中文版本
生成AI智能校验的中文版本