加载中…
Two words and are avoided by the same number of length- words, for all , precisely when and have the same set of border lengths. Previous proofs of this theorem use generating functions but do not provide an explicit bijection. We give a bijective proof for all pairs that have the same set of proper borders, establishing a natural bijection from the set of words avoiding to the set of words avoiding .

生成讲解博客的中文版本

生成AI智能校验的中文版本