Roots of outer automorphisms of free groups and centralizers of abelian subgroups of $\mathrm{O}\mathrm{u}\mathrm{t}(F_N)$

Let $N\ge 2$ and let $\mathrm{O}\mathrm{u}\mathrm{t}(F_N)$ be the outer automorphism group of a nonabelian free group of rank $N$. Let ${\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$ be the finite index subgroup of $\mathrm{O}\mathrm{u}\mathrm{t}(F_N)$ which is the kernel of the natural action of $\mathrm{O}\mathrm{u}\mathrm{t}(F_N)$ on $H_1(F_N,\mathbb{Z}\mathrm{/}3\mathbb{Z})$. We show that ${\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$ is an $R$-group, that is, for every $\phi ,\psi \in {\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$, if there exists $k\in {\mathbb{N}}^{\ast }$ such that ${\phi }^k={\psi }^k$, then $\phi =\psi$. This answers a question of Handel and Mosher. We then use the fact that ${\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$ is an $R$-group in order to prove that the normalizer in ${\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$ of every abelian subgroup of ${\mathrm{I}\mathrm{A}}_N(\mathbb{Z}\mathrm{/}3\mathbb{Z})$ is equal to its centralizer. We finally give an alternative proof of a result, due to Feighn and Handel, that the centralizer of an element of $\mathrm{O}\mathrm{u}\mathrm{t}(F_N)$ which has only finitely many periodic orbits of conjugacy classes of maximal cyclic subgroups of $F_N$ is virtually abelian.