Further Applications of Cubic $q$-Binomial Transformations

Consider \begin{align*} G(N,M;α,β,K,q) = \sum\limits_{j\in$\mathbb{Z}$}(-1)^jq^{\frac{1}{2}Kj((α+β)j+α-β)}\left[\begin{matrix}M+N\N-Kj\end{matrix}\right]{q}. \end{align*} In this paper, we prove the non-negativity of coefficients of some cases of $G(N,M;\alpha ,\beta ,K,q)$. For instance, for non-negative integers $n$ and $t$, we prove that\ \begin{align*} G\left(n,n;\frac{4}{3}+\frac{3(3^t-1)}{2},\frac{5}{3}+\frac{3(3^t-1)}{2},3^{t+1},q\right) \end{align*} and \begin{align*} G\left(n-\frac{3^t-1}{2},n+\frac{3^t+1}{2};\frac{8}{3}+2(3^t-1),\frac{4}{3}-(3^t-1),3^{t+1},q\right)\ \end{align*} are polynomials in $q$ with non-negative coefficients. Using cubic positivity preserving transformations of Berkovich and Warnaar and some known formulae arising from Rogers-Szegö polynomials, we establish new identities such as\ \begin{align*} \sum\limits{0\le 3j\le n}\dfrac{(q^3;q^3){n-j-1}(1-q^{2n})q^{3j^2}}{(q;q){n-3j}(q^6;q^6){j}} = \sum\limits{j=-\infty}^{\infty}(-1)^jq^{6j^2}{2n\brack n-3j}_q. \end{align*}