We show how to prove by means of the Lagrange inversion the limit of Arnol’d that limx→0sin(tanx)−tan(sinx)arcsin(arctanx)−arctan(arcsinx)=1 .x→0limarcsin(arctanx)−arctan(arcsinx)sin(tanx)−tan(sinx)=1. In fact, we obtain a more general result in terms of formal power series.
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