We prove that every embedding of K2n+1,2n+1K2n+1,2n+1 into R3R3 contains a non-split link of nn-components. Further, given an embedding of K2n+1,2n+1K2n+1,2n+1 in R3R3, every edge of K2n+1,2n+1K2n+1,2n+1 is contained in a non-split nn-component link in K2n+1,2n+1K2n+1,2n+1.
生成讲解博客的中文版本
生成AI智能校验的中文版本