We consider the group M of all polynomial matrices U(z) = U0 + U1z + U2zz +…+Ukz*…z, k=0,1,… that satisfy equation U(z)DU(z)" = D with the diagonal nn matrix D=diag{-1,1,1,…1}. Here n > 1, U(z)" = U0" + U1"z + U2"zz + …, and symbol A" for a constant matrix A denotes the Hermitiean conjugate of A. We show that the subgroup M0 of those U(z) in M, that are normalized by the condition U(0)=I, is the free product of certain groups. The matrices in each group-multiples are explicitly and uniquely parametrized so that every U=U(z) in M0 can be represented in the form U = G1 * G2 * … * Gs with nn polynomial matrix multiples G1, G2, …, each of which belong to its group-multiple, and so that any two consecutive Gi and G(i+1) belong to two different group-multiples. The uniqueness of such parametrization for a given U includes the number of multiples s, their particular sequence G1,G2,… and the multiples themselves with their respective parametrization; all these items can be defined in only one way once the U is given.

生成讲解博客的中文版本

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