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Using the formulas for the distribution with non-zero lepton mass and experimentally determined form factors, we calculate the $d\Gamma (D^{()+} l^- {\bar{\nu}})/ dq^2l=e\mu\tau{\cal{B}}({\bar{B}}^0\rightarrow D^{+} \tau^- {\bar{\nu}})/ {\cal{B}}({\bar{B}}^0\rightarrow D^{+} e^- {\bar{\nu}})= 0.278^{+0.049}_{-0.035}{\cal{B}}({\bar{B}}^0\rightarrow D^{+} \tau^- {\bar{\nu}})/ {\cal{B}}({\bar{B}}^0\rightarrow D^{*+} e^- {\bar{\nu}})= 0.256^{+0.014}_{-0.013}$ . Since we used the experimentally measured form factors, these results are independent of theoretical models of form factors.

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