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Given an expansive matrix and a finite set of digit taken from . It was shown previously that if we can find an such that forms a Hadamard triple, then the associated fractal self-affine measure generated by admits an exponential orthonormal basis of certain frequency set , and hence it is termed as a spectral measure. In this paper, we show that if #$B<|\det ®|$, not only it is spectral, we can also construct arbitrarily sparse spectrum in the sense that its Beurling dimension is zero.

生成讲解博客的中文版本

生成AI智能校验的中文版本