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Let be an odd prime and let be a positive integer. For any positive integer and , we have \begin{align*} \sum_{k=0}^{p^{\alpha}n-1}\frac{(\frac12)k}{k!}\cdot\frac{(-4)^k}{m^k}\equiv\bigg(\frac{m(m-4)}{p}\bigg)\sum{k=0}^{p^{\alpha-1}n-1}\frac{(\frac12)k}{k!}\cdot\frac{(-4)^k}{m^k}\pmod{p^{2\alpha}}, \end{align*} where and denotes the Legendre symbol. Also, when , \begin{align*} \sum{k=0}^{p^{\alpha}n-1}(-1)^k\cdot\frac{(\frac12)k}{k!}\equiv p\sum{k=0}^{p^{\alpha-1}n-1}(-1)^k\cdot\frac{(\frac12)_k}{k!}\pmod{p^{2\alpha}}. \end{align*}

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