Let G be a unique product group, i.e., for any two finite subsets A and
B of G there exists x∈G which can be uniquely expressed as a product
of an element of A and an element of B. We prove that, if C is a finite
subset of G containing the identity element such that ⟨C⟩ is
not abelian, then for all subsets B of G with ∣B∣≥7, $|BC|\geq |B| +
|C| + 2.Also,weprovethatifC$ is a finite subset containing the identity
element of a torsion-free group G such that ∣C∣=3 and ⟨C⟩
is not abelian, then for all subsets B of G with ∣B∣≥7, $|BC|\geq |B|
- 5.Moreover,if\langle C\rangle$ is not isomorphic to the Klein bottle
group, i.e., the group with the presentation $\langle x, y ;|; xyx =
y\rangle,thenforallsubsetsBofGwith|B|\geq 5,|BC|\geq |B| + 5$.
The support of an element α=∑x∈Gαxx a group algebra
F[G] (F is any field), denoted by supp(α), is the set ${x\in G
;|; \alpha_x \neq 0}.Bythelatterresult,weprovethatif\alpha \beta
= 0forsomenon−zero\alpha,\beta \in F[G]suchthat|supp(\alpha)| = 3$,
then ∣supp(β)∣≥12. Also, we prove that if αβ=1 for some
αβ∈F[G] such that ∣supp(α)∣=3, then |supp(\alpha)|\geq
10$. These results improve a part of results in Schweitzer [J. Group Theory, 16
(2013), no. 5, 667-693] and Dykema et al. [Exp. Math., 24 (2015), 326-338] to
arbitrary fields, respectively.