加载中…
Let be the first Grigorchuk group. According to a result of Bartholdi, the only left Engel elements of are the involutions. This implies that the set of left Engel elements of is not a subgroup. Of particular interest is to wonder whether this happens also for the sets of bounded left Engel elements, right Engel elements, and bounded right Engel elements of . Motivated by this, we prove that these three subsets of coincide with the identity subgroup.

生成讲解博客的中文版本

生成AI智能校验的中文版本