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Let denote the degree dilation of a point set in the domain of plane geometric spanners. If is the infinite square lattice, it is shown that $1+\sqrt{2} \leq \delta_0(\Lambda,3) \leq (3+2\sqrt2) , 5^{-1/2} = 2.6065\ldots\delta_0(\Lambda,4) = \sqrt{2}\Lambda\delta_0(\Lambda,3) = 1+\sqrt{3}\delta_0(\Lambda,4) = 2$. All our constructions are planar lattice tilings constrained to degree or .

生成讲解博客的中文版本

生成AI智能校验的中文版本