In this article, we consider the reciprocal antisymmetric polynomial P(z)=j=0∑s(−1)jγj(zj−zN+s+1−j), γ0=1. It is shown that if all the zeros of P(z) are located on the unit circle, that ∣γj∣≤(js)((jN+s+1))−1, j=1,…,s; moreover, these estimates cannot be improved in the general case. Factorization formulas for extremal polynomials are given: aj=0∑s(−1)j(js)((jN+s+1))−1(zj−zN+s+1−j)=(1−z)2s+1j=1∏[2N−s][z2+1+2z(1−2(νj)2)]{(1+z),1,N−sisoddN−siseven where {νj}j=1[2N−s] is the set of positive zeros of the polynomial UN(s)(z) given UN(z)=j=0∑[2N](−1)jj!(N−2j)!(N−j)!(2z)N−2j are the Chebyshev Polynomials of the Second Kind and UN(s)(z) is the sth derivative of UN(z). As an application of the results, formulas were obtained expressing the derivatives of Chebyshev polynomials of the second kind through linear combinations of Chebyshev polynomials of the second kind: s!2s(1−z2)sUN(s)(z)=(−1)sj=0∑s(−1)j(N−sN−j)(jN+s+1)UN+s−2j(z).