Given non-negative integers , the Hamilton-Waterloo problem asks for a factorization of the complete graph into -factors and -factors. Clearly, odd, , $m\mid vn\mid v\alpha+\beta = (v-1)/2$ are necessary conditions. To date results have only been found for specific values of and . In this paper we show that for any and the necessary conditions are sufficient when is a multiple of and , except possibly when or 3, with five additional possible exceptions in . For the case where we show sufficiency when except possibly when $(m,\alpha) = (3,2)(3,4)(m,n,\alpha,\beta)n\geq m\geq 3$ are odd integers, the lexicographic product of with the empty graph of order has a factorization into -factors and -factors for every , , except possibly when , , with three additional possible exceptions in .

生成讲解博客的中文版本

生成AI智能校验的中文版本