$Z_c(3900)$ as a Four-Quark State

Using the method of QCD Sum Rules, we derive the correlator ${\mathrm{\Pi }}^Z$ for a state consisting of two charm quarks and two light quarks, $c\bar{c}u\bar{d}$, and carry out a Borel transform to find ${\mathrm{\Pi }}^Z(M_B)$. From this we find the solution that $M_B\simeq 3.9\pm .2$ GeV, showing that the $Zc(3900)$ is a tetra-quark state.