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A finite tree with is called {\it automorphism-free} if there is no non-trivial automorphism of . Let be the poset with the element set of all finite automorphism-free trees (up to graph isomorphism) ordered by if can be obtained from by successively deleting one leaf at a time in such a way that each intermediate tree is also automorphism-free. In this paper, we prove that has a unique minimal element. This result gives an affirmative answer to the question asked by Rupinski.

生成讲解博客的中文版本

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