The Large Davenport Constant I: Groups with a Cyclic, Index 2 Subgroup

Let $G$ be a finite group written multiplicatively. By a sequence over $G$, we mean a finite sequence of terms from $G$ which is unordered, repetition of terms allowed, and we say that it is a product-one sequence if its terms can be ordered so that their product is the identity element of $G$. The small Davenport constant $\mathsf{d}(G)$ is the maximal integer $\mathrm{\ell }$ such that there is a sequence over $G$ of length $\mathrm{\ell }$ which has no nontrivial, product-one subsequence. The large Davenport constant $\mathsf{D}(G)$ is the maximal length of a minimal product-one sequence—this is a product-one sequence which cannot be factored into two nontrivial, product-one subsequences. It is easily observed that $\mathsf{d}(G)+1\le \mathsf{D}(G)$, and if $G$ is abelian, then equality holds. However, for non-abelian groups, these constants can differ significantly. Now suppose $G$ has a cyclic, index 2 subgroup. Then an old result of Olson and White (dating back to 1977) implies that $\mathsf{d}(G)=\frac{1}{2}\mathrm{\mid }G\mathrm{\mid }$ if $G$ is non-cyclic, and $\mathsf{d}(G)=\mathrm{\mid }G\mathrm{\mid }-1$ if $G$ is cyclic. In this paper, we determine the large Davenport constant of such groups, showing that $\mathsf{D}(G)=\mathsf{d}(G)+\mathrm{\mid }{G}^{\mathrm{\prime }}\mathrm{\mid }$, where $G’=[G,G]\leq G$isthecommutatorsubgroupof$G$.