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We prove that on , there is no -supercyclic operator with i.e. if has an dimensional subspace whose orbit under is dense in , then is greater than . Moreover, this value is optimal. We then consider the case of strongly -supercyclic operators. An operator is strongly -supercyclic if has an -dimensional subspace whose orbit under is dense in , the -th Grassmannian. We prove that strong -supercyclicity does not occur non-trivially in finite dimension.

生成讲解博客的中文版本

生成AI智能校验的中文版本