Split cuts are cutting planes for mixed integer programs whose validity is derived from maximal lattice point free polyhedra of the form $S:={x : \pi_0 \leq \pi^T x \leq \pi_0+1 }$ called split sets. The set obtained by adding all split cuts is called the split closure, and the split closure is known to be a polyhedron. A split set has max-facet-width equal to one in the sense that . In this paper we consider using general lattice point free rational polyhedra to derive valid cuts for mixed integer linear sets. We say that lattice point free polyhedra with max-facet-width equal to have width size . A split cut of width size is then a valid inequality whose validity follows from a lattice point free rational polyhedron of width size . The -th split closure is the set obtained by adding all valid inequalities of width size at most . Our main result is a sufficient condition for the addition of a family of rational inequalities to result in a polyhedral relaxation. We then show that a corollary is that the -th split closure is a polyhedron. Given this result, a natural question is which width size is required to design a finite cutting plane proof for the validity of an inequality. Specifically, for this value , a finite cutting plane proof exists that uses lattice point free rational polyhedra of width size at most , but no finite cutting plane proof that only uses lattice point free rational polyhedra of width size smaller than . We characterize based on the faces of the linear relaxation.

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