加载中…
The double sum sum_(s >= 1) sum_p 1/(p^s log p^s) = 2.00666645… over the inverse of the product of prime powers p^s and their logarithms, is computed to 24 decimal digits. The sum covers all primes p and all integer exponents s>=1. The calculational strategy is adopted from Cohen’s work which basically looks at the fraction as the underivative of the Prime Zeta Function, and then evaluates the integral by numerical methods.

生成讲解博客的中文版本

生成AI智能校验的中文版本