加载中…
Let be the continued fraction expansion of . We prove that the Hausdorff dimension of \begin{equation*}E_{even}={x\in[0,1)\colon a_{2n}(x)\to\infty\ (n\to\infty)}.\end{equation*} is 1/2. In general, we study the set of continued fractions with unbounded partial quotients along subsequence \begin{equation*}E_{{k_n}}={x\in[0,1)\colon a_{k_n}(x)\to\infty\ (n\to\infty)},\end{equation*} where is a subsequence. We show that has Hausdorff dimension 1/2 or 1 according to whether the set of indices has positive or zero upper density respectively.

生成讲解博客的中文版本

生成AI智能校验的中文版本