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Let be an ordinary polynomial in with no negative exponents and with no factor of the form $z_1^{\alpha_1}… z_n^{\alpha_n}\alpha_i$ are non zero natural integer. If we assume in addicting that is maximally sparse polynomial (that its support is equal to the set of vertices of its Newton polytope), then a complement component of the amoeba in of the algebraic hypersurface defined by , has order lying in the support of , which means that is solid. This gives an affirmative answer to Passare and Rullg\aa rd question in [PR2-01].

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