We prove a sharp quantitative version of the Talenti rearrangement inequality. Specifically, we show that, for any , for any , for any open set with finite volume, the solution to , satisfies, in dimension , and, in dimension 1, where denotes the Fraenkel asymmetry of , a weighted asymmetry of with respect to some center and (resp. ) is the Schwarz rearrangement of (resp. of ). In dimension , this estimate implies Our result sharpens and extends recent quantitative versions, and does not rely on shape differentiation arguments, but on a generalisation of the quantitative Saint-Venant inequality.

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