We prove that there exists A⊆NA⊆N such that RA(N)=π4N+O (N1/4logN),RA(N)=4πN+O(N1/4logN), where RA(N)=#{(a,b)∈A2:a+b≤N}RA(N)=#{(a,b)∈A2:a+b≤N}. This improves the record O(N1/4logN)O(N1/4logN) obtained by Ruzsa in 1997.
生成讲解博客的中文版本
生成AI智能校验的中文版本